2n^2-12n-28=4

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Solution for 2n^2-12n-28=4 equation:


Simplifying
2n2 + -12n + -28 = 4

Reorder the terms:
-28 + -12n + 2n2 = 4

Solving
-28 + -12n + 2n2 = 4

Solving for variable 'n'.

Reorder the terms:
-28 + -4 + -12n + 2n2 = 4 + -4

Combine like terms: -28 + -4 = -32
-32 + -12n + 2n2 = 4 + -4

Combine like terms: 4 + -4 = 0
-32 + -12n + 2n2 = 0

Factor out the Greatest Common Factor (GCF), '2'.
2(-16 + -6n + n2) = 0

Factor a trinomial.
2((-2 + -1n)(8 + -1n)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-2 + -1n)' equal to zero and attempt to solve: Simplifying -2 + -1n = 0 Solving -2 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1n = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1n = 0 + 2 -1n = 0 + 2 Combine like terms: 0 + 2 = 2 -1n = 2 Divide each side by '-1'. n = -2 Simplifying n = -2

Subproblem 2

Set the factor '(8 + -1n)' equal to zero and attempt to solve: Simplifying 8 + -1n = 0 Solving 8 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '-8' to each side of the equation. 8 + -8 + -1n = 0 + -8 Combine like terms: 8 + -8 = 0 0 + -1n = 0 + -8 -1n = 0 + -8 Combine like terms: 0 + -8 = -8 -1n = -8 Divide each side by '-1'. n = 8 Simplifying n = 8

Solution

n = {-2, 8}

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